Have a look at wizbake.com

Subscribe to our monthly newsletter by clicking here 

REDUCE OPERATING COSTS BY INSTALLING THERMCO™ COVERS - REMOVABLE REUSABLE INSULATION

Large Savings Can Be Achieved

Conventional insulation methods are in many instances not used on plant equipment such as valves, flanges, manhole covers and others where periodic access is necessary for inspection and maintenance.

Uninsulated areas of such plant items are deceptively large and heat losses are high.

Ever increasing demands for improved efficiency to reduce costs generally focus attention on manpower and other areas which are reflected in operating costs. ENERGY SAVING sometimes does not receive enough attention with specific reference to heat losses of uninsulated areas.

Where insulation has to be removed, THERMCO™ Covers provide the economical and practical solution.

Cost Of Lost Energy

The annual cost of lost energy is determined by:

1. Actual heat loss per square metre

2. Cost or value of this heat loss

3. Number of hours per year the system is in operation.

Production cost of lost energy has to be estimated including:

1. Fuel or power costs

2. Capital equipment costs

3. Operating and maintenance costs of the capital equipment.

The most significant component of energy cost is fuel or electricity cost. Naturally these will vary in different geographic areas and are also influenced by the efficiency of conversion. Further, fuel and power costs are certain to increase over the planned lifetime of the insulation.

EVALUATION OF ENERGY COST SAVINGS AFTER INSULATION WITH THERMCO™ COVERS

1. Calculate the area in sq.m. of uninsulated plant item = A

2. Heat saved in kW (Watts/1000) from heat loss tables - taking into account wind factor if any = HS

3. Energy cost per kWHr = EC

4. Operating hours per annum = HRS

SAVING IN MONEY PER ANNUM

Saving = A x HS x EC x HRS

PAYBACK PERIOD OF INVESTMENT IN COVER

Payback time = (Cost of Insulation Cover / Saving per annum) x 12 = months

EXAMPLE

A 300mm nominal bore flanged joint 300lb rating with 20 M32 nuts, process temperature of 260°C, operating 8740 hours p.a., power cost steam ZAR 0.022 per kWHr, calculated area 1.061sq.m. with 0km/h wind.

Heat Saved - Watts / sq.m.

50mm Thick Insulation Cover

Saving per annum = 1.061 x 0.022 x 4765 / 1000 x 8740 = ZAR 972.00

Cost of insulation cover = ZAR 614.00

Payback period would be = (614 / 972) x 12 = 7.6 months

Best viewed with a screen resolution of 1024 x 768

Send mail to webmaster@cofab.co.za with questions or comments about this web site.
Copyright © 2004 Coated Fabrics (SA) Pty) Ltd
Last modified: 04/12/06